Start - 11:00 AM
Based on yesterday's session and the pain that was CFAI probability, I think that a recap of probability using Schweser is in order. Scanning over the Schweser notes it seems like they do a much better job explaining the concepts so I am going to try an quickly do the Schweser for the same Reading #8 that we did yesterday. This will also be useful for getting an idea of how Schweser compares to CFAI in terms of depth, content, and difficulty.
Intro
Probability P(Ei) for any event Ei must be 0<=P(Ei)<=1
If events are mutually exclusive and exhaustive, sum of all probabilities = 1
Types of Probability
Rules
Based on yesterday's session and the pain that was CFAI probability, I think that a recap of probability using Schweser is in order. Scanning over the Schweser notes it seems like they do a much better job explaining the concepts so I am going to try an quickly do the Schweser for the same Reading #8 that we did yesterday. This will also be useful for getting an idea of how Schweser compares to CFAI in terms of depth, content, and difficulty.
Intro
- Random variable - uncertain quantity/number (number that comes up on a dice)
- Outcome - observed value of a random variable (if you roll a 4)
- Event - single outcome or set of outcomes (rolling a 4)
- Mutually exclusive - events that can't both happen at same time (rolling a 4 and rolling a 6)
- Exhaustive events - those that include all possibilities (rolling an even and rolling an odd)
Probability P(Ei) for any event Ei must be 0<=P(Ei)<=1
If events are mutually exclusive and exhaustive, sum of all probabilities = 1
Types of Probability
- Empirical - established on past data (DJIA closes higher than previous close 2/3 days => future probability is 2/3)
- A priori - using a formal reasoning process (yesterday 24/30 stocks rose; if you pick on at random there is a 24/30 chance its value increased yesterday)
- Subjective - based on personal feeling
- "Odds" that an event will occur are P / (1-P) = the p it will occur to the p it won't occur
- Given a set of odds a/b, to calculate the P, it is a/(a+b)
- E.g. if odds of winning are 1 to 7, P(winning) = 1 / (1+7) = 1/8 or 12.5%
- Unconditional Probability - probability of an event regardless of past or future occurrences of other event
- Conditional - probability of an event given that another event has happened - look for words "given" or "conditional upon"
Rules
- Multiplication - determine joint probability: P(AB) = P(A|B)*P(B)
- Addition - determine that at least 1 of 2 events occurs
- P(A or B) = P(A) + P(B) - P(AB)
- Total Probability Rule - determines the unconditional prob of an event, given conditionals
- P(A) = P(A|B1)(B1) + P(A|B2)(B2) + ... + P(A|Bn)(Bn)
- B1 to Bn is a set of MECE outcomes
Interpretation
- Joint probability of two events - probability they will both occur - multiplication rule
- Prob that at least one of two events will occur - addition rule
- Joint probability of more than two events - keep multiplying
- Dependent/Independent
- For independent events, P(A|B)=P(A). Likewise P(B|A)=P(B)
Calculating an unconditional prob using the total probability rule
- Sum of the joint probabilities is the unconditional probability of an event
- Example
- P(I) = 0.4, the prob that the authorities raise interest rates
- P(R|I) = 0.7, prob of a recession given that rates rise
- P(R|Ic) = 0.1, prob of a recession if rates do NOT rise
- What is the unconditional probability of a recession?
- P(R|I)*P(I) + P(R|Ic)*P(Ic)
- We know P(Ic) = 1-P(I) = 1 - 0.4 = 0.6
- So 0.7*0.4 + 0.1*0.6 = 0.28 + 0.06 = 0.34
- EV is simply a weighted average of the outcomes, weighted by probability
- To calculate variance:
- Subtract EV from each outcome and square the difference
- Multiply by probability
- Add all these up
- Standard deviation is the square root of this
- Expected values can be conditional - i.e. 'conditional expected values'
- Analyst would use a conditional expected value to revise estimate when new information arrives
- Using a tree to find expected value:
Covariance and Correlation
- Covariance - measure of how two assets move together - Cov(X,Y). We are usually concerned with the covariance of returns.
- Covariance is the expected value of the product of deviations of two random variables from their respective expected values
- Cov (Ri, Rj) = E{[Ri - E(Ri)]*[Rj - E(Rj)]}
- The covariance of a variable with itself is equal to its variance
- Covariance can range from negative infinity to positive infinity
Assume probabilities and returns as follows:
- First find expected returns of each stock A and B
- E(Ra) = 0.3*0.2 + 0.5*0.12 + 0.2*0.05 = 0.13
- E(Rb) = 0.14
- To get covariance, now do Return minus Expected for each row/security, and multiply together and then by probability, and then sum
- Ex. in row Boom, do 0.3 * (0.20 - 0.13) * (0.30 - 0.14) = 0.00336
- Same approach in rows Normal and Slow give 0.00020 and 0.00224
- Covariance is the sum of these three numbers: 0.00580
- Covariance though is difficult to interpret - so we use correlation
- Correlation = Covariance / (SdevA * SdevB)
- Ex. given the covariance of 0.00580 from previous, and Var(Ra) = 0.0028 and Var(Rb) = 0.0124, what is correlation?
- Remember to convert Variances to sdevs (take sqrts)
- 0.0058 / (0.0028^0.5*0.0124^0.5) = 0.9824
Calculating EV and variance for a portfolio
- EV and variance for a portfolio can be determined using the properties of the individual assets in the portfolio
- First, establish portfolio weight for each asset: w = mkt value of investment / mkt value portfolio
- Expected value and expected return are just a weighted average
- (This is a very difficult formula and I don't expect to study it frankly
There is more information and examples on how to calculate variance, covariance, etc for portfolios that I don't want to go into at this point.
Bayes' formula
- This is used to update a given set of prior probabilities for a given event in response to the arrival of new information
- updated prob = (probability of new information / unconditional prob of new information) * prior prob of the event
- Tree model made sense to me but the Electrocomp example made no sense - perhaps ask a friend for help on Bayes
Counting Problems
- Labeling - n items can each receive one of k different labels
- Ex - you have a portfolio of 8 stocks. You want to label 4 as long holds, 3 as short term holds, and 1 as sell.
- Number of ways = n! / (n1!*n2!*...*nk!)
- = 8! / (4! * 3! * 1!) = 40,320 / (24*6*1) = 280 combinations
- Note - there is a special case when n = 2
- Number of ways = n! / ((n-r)!r!)
- Permutation - a specific ordering of a group of objects
- 'How many different groups of size r can be chosen from n objects'
- Permutations = n! / (n-r)!
- Ex how many ways can 3 stocks be sold from an 8 stock portfolio if order is important?
- Permutations = 8! / (8-3)! = 40,320 / 120 = 336
- if order not important, 8! / ((8-3)!*3!) = 40,320 / 720 = 56
- Rules and hints
- Multiplication rule - if there are k steps to do something and each step can be done n ways, there are n1! * n2! * ... *nk! ways to do it
- Factorial - given n items, there are n! ways to arrange them
- Labeling is for when you have 3 or more subgroups of predetermined size and each element must be assigned a place (label) in one of the subgroups
- Combination - only applies to when there are only 2 groups of predetermined size - look for 'choose' or 'combination'
End of reading.
1:30 pm
About 2.5 hours
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